Cos(90-x)+sin^2x=0

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Solution for Cos(90-x)+sin^2x=0 equation:


Simplifying
Cos(90 + -1x) + sin2x = 0
(90 * osC + -1x * osC) + sin2x = 0
(90osC + -1osxC) + sin2x = 0

Reorder the terms:
in2sx + 90osC + -1osxC = 0

Solving
in2sx + 90osC + -1osxC = 0

Solving for variable 'i'.

Move all terms containing i to the left, all other terms to the right.

Add '-90osC' to each side of the equation.
in2sx + 90osC + -90osC + -1osxC = 0 + -90osC

Combine like terms: 90osC + -90osC = 0
in2sx + 0 + -1osxC = 0 + -90osC
in2sx + -1osxC = 0 + -90osC
Remove the zero:
in2sx + -1osxC = -90osC

Add 'osxC' to each side of the equation.
in2sx + -1osxC + osxC = -90osC + osxC

Combine like terms: -1osxC + osxC = 0
in2sx + 0 = -90osC + osxC
in2sx = -90osC + osxC

Divide each side by 'n2sx'.
i = -90n-2ox-1C + n-2oC

Simplifying
i = -90n-2ox-1C + n-2oC

Reorder the terms:
i = n-2oC + -90n-2ox-1C

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